Aviation Training Experts™

handbook

Aviation Maintenance Technician Handbook–Airframe

FAA-H-8083-31B Version 2023

Chapter 9

Aircraft Electrical System

Next solve for capacitive reactance:

Formula: 1 ; XC = ; 2π ; fC ; 1 ; XC = ; 2π(60) ( ; .00020) ; 1 ; XC = ; 0.0 7 ; 536 ; XC = 13Ω

To find the impedance,

Formula: Z = √ R2 + XC 2 ; Z = √ 102 + 132 ; Z = 16.4Ω

Since this circuit is resistive and capacitive, there is a phase shift where current leads voltage:

To find the current:

Formula: E ; IT = ; Z ; IT = 1 ; 1 ; 0 ; V ; 6 ; .4 ; Ω ; IT = 6.7 amps

To find the voltage drop across the resistor (ER):

Formula: ER = I × R ; ER = 6.7A × 10Ω ; ER = 67 volts

To find the voltage drop over the capacitor (EC):

Formula: EC = I × XC ; EC = 6.7A × 13Ω
Formula: EC = 86.1 volts

The sum of these two voltages does not equal the applied voltage, since the current leads the voltage. Use the following formula to find the applied voltage:

Formula: E = √ (ER)2 + (EC)2 ; E = √ 672 + 86.12 ; E = √ 4,489 + 7,413 ; E = √ 11,902 ; E = 110 volts

When the circuit contains resistance, inductance, and capacitance, the following equation is used to find the impedance.

Formula: Z = √ R2 + (XL – XC)2

Example 3: What is the impedance of a series circuit consisting of a capacitor with a capacitive reactance of 7 ohms, an inductor with an inductive reactance of 10 ohms, and a resistor with a resistance of 4 ohms? [Figure 9-27]

Solution:

Formula: Z = √ R2 + (XL – XC)2 ; Z = √ 42 + (10 – 7)2
Figure 9-27. A circuit containing resistance, inductance, and capacitance.
Figure 9-27. A circuit containing resistance, inductance, and capacitance.